Thread: What does **++argv mean

  1. #1
    Registered User
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    What does **++argv mean

    Code:
    #include<stdio.h>
    int main(int argc , char *argv[])
               {
                   printf("%c\n",**++argv);
               }
    ./a.out 5 gives the output 5
    Code:
    #include<stdio.h>
    int main(int argc , char *argv[])
               {
                   printf("%c\n",*argv[1]);
               }
    ./a.out 5 gives the output 5

    is **++argv sameas *argv[1]?
    can any one explain

  2. #2
    [](){}(); manasij7479's Avatar
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    is **++argv sameas *argv[1]
    Yes.
    In general,
    a[x] is same as *(a + x)

  3. #3
    C++ Witch laserlight's Avatar
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    Actually, no, they are not equivalent. Recall that ++argv modifies argv, but argv[1] does not.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  4. #4
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    If these work, then **++argv is the same as *(++argv)[0] or (++argv)[0][0].

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