Thread: What does **++argv mean

Code:

#include<stdio.h>
int main(int argc , char *argv[])
           {
               printf("%c\n",**++argv);
           }

./a.out 5 gives the output 5

Code:

#include<stdio.h>
int main(int argc , char *argv[])
           {
               printf("%c\n",*argv[1]);
           }

./a.out 5 gives the output 5

is **++argv sameas *argv[1]?
can any one explain

is **++argv sameas *argv[1]

Yes.
In general,
a[x] is same as *(a + x)

If these work, then **++argv is the same as *(++argv)[0] or (++argv)[0][0].