I am creating a while loop that runs for two values of i and j. If the value of j is a new low, I output 20 million dollars. I'm running into a problem because the loop can bring j back up and then back to that same number and I don't know how to stop it from outputting 20 million again.
Thank you guys.
I suggest that you post the smallest and simplest compilable program that demonstrates the problem.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
It's a pretty convoluted code. I am supposed to add a scenario where the bond rating drops to a new low and the agency pays out 20,000,000. I know that when j < i, we've that the bond rating when down. But the loop can run again twice and go from j>i back to j < i and we're at the same rating, but it went down so the program wants to payout 20millionCode:// Determine new credit rating via inverse transform. U = MTUniform (0); // This can be made more efficient!! int jmin; jmin = (i >= 1 ? i-1 : 0); for (j = jmin; j <= 8; j++) { if (U <= P[i][j]) { break; } if {j<i} payout+=20,000,000 }
Your code snippet certainly is not compilable.
The solution sounds simple: you could use a flag, or maybe you could check for some value. I am afraid that I can only be vague because you only have a vague code snippet to examine.
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Vague is actually what I want because the solution is complicated numerically so it requires me to know how to do this. How would I use a "flag"? Could you give an example?
A flag might work like this, in pseudocode:
However, thinking more carefully about your problem, this probably doesn't apply. You would probably use the "check some value" solution, in this case perhaps the lowest value, i.e.,Code:payout_flag = false if (whatever && !payout_flag) { make payout payout_flag = true }
Code:if (new low < lowest value) { make payout lowest value = new low }
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