operator precedence in C

[dimps]

hi,i am new to C programming and I am a little confused about operator precedence. I wrote a program in which


x=3
z=x<10
i also tried with z=x>10
for both I am getting z=0 as output.
why so?
as far as I know > has precedence and x<10 so a true statement and z must be =1. can I have more details plz?

[laserlight]

I did a quick test with this program:

#include <stdio.h>

int main(void)
{
    int x = 3;
    int z = x < 10;
    printf("%d\n", z);
    return 0;
}

The output that I got:

1

So you would need to prove otherwise by showing the program that you actually tested.

[Stark88]

you are right the output should be 1, maybe the compiler you are using does things differently.

[laserlight]

you are right the output should be 1, maybe the compiler you are using does things differently.

Possible, but if so, dimps' (or your) compiler has a serious bug because according to the language rules, the output that I received is correct. Did you compile and run the code that I posted? What output did you get?

[dimps]

I use an online compiler. Here is the program I was trying to execute:

#include <stdio.h>

int main()
{
     int x=3,y,z;
     y=x=10;
     z=x<10;
     printf("x=%d\t y=%d\tz=%d\n",x,y,z);
}

and the output shows:
x=10 y=10 z=0
x=10 y=10 z=0
sh-4.3$ ^C

[GReaper]

The output is 100% correct then. It says so right there, x is 10. 10 is neither smaller nor larger than 10...

[dimps]

You are so right.thank you all