Thread: New to programming need some help

Hi guys,
I just started out and I am having some difficulty getting my program to work. I was following an online guide to this program but it ended sorta midway and I am left quite baffled.

Code:

#include <stdio.h>


int main (void)
{
    int userAge;
    
    printf("How old are you?\n");
    scanf("%d", &userAge);
    
    char citizen[3] = {'\0'};
    printf("Are you a citizen of the USA?\n");
    scanf("%s", citizen);
    
   if (userAge >= 18 && citizen == ("yes")) {
               printf ("Yup ya can vote boo. Go get 'em");
        }
   else {
               printf("You are not eligible to vote. Soz.");
        }
    getchar ();
    getchar ();
    
    return 0;
}

The problem is the citizen variable. I want the user to input a positive or negative answer to the question but I am pretty sure I am doing it wrong. Can anyone help out? Plus if you could I would really appreciate if you could explain to me why do I need the & character before userAge?

And of course I would greatly appreciate if you had any online course to recommend that would cater to my basic needs

Have a great day!

Well part of the problem may be that you don't have enough room in your citizen array. You only have room for two characters plus the end of string character. Also you can't use the comparison operator to compare two strings, you need to investigate strcmp().

Jim

Plus if you could I would really appreciate if you could explain to me why do I need the & character before userAge?

Code:

scanf("%d", &userAge);

'&' is the "address-of" operator. "scanf()" needs the address of the given variable so that the variable can be updated. You will learn more about this behavior when you study pointers.