Thread: Can someone help me with a school project

Hey all,

I'm new here and came here to ask you a question about my school exercise but can't find out what the problem is...

I need to scan in one file where numbers are fully written in 20 sentences and I need to print them in the good order in another file. from high to low starting at 20

I've set up a long else if statement from 0 to 20 (in Dutch) but I can't get any further. I was thinking to get them into a 2D array so 20 gets on out[0], 19 on out[1], etc.

Now that's a problem that isn't going that well.
After that I just need to fprintf it in the file.

Can someone help me?

The source code I have now:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>



int main (int argc, char *argv[]) {
    char regel [255];
    char out [25][255];
    FILE *myFile;
    FILE *myFile1;

    myFile = fopen (argv[1], "r");      //in
    if (myFile == NULL) {         // foutmelding
        printf ("leesfout\n");
        return -1;
    }

    myFile1 = fopen (argv[2], "r");     //out
    if (myFile1 == NULL) {         // foutmelding
        printf ("leesfout\n");
        return -1;
    }


    while (fgets (regel, 255, myFile) != NULL)  {
        if(regel[0]=='t' && regel[3]=='a') {        //twintig

        }else if(regel[0]=='n' && regel[7]=='e'){   //negentien

        }else if(regel[0]=='a' && regel[5]=='e'){   //achtien

        }else if(regel[0]=='z' && regel[5]=='t'){   //zeventien

        }else if(regel[0]=='z' && regel[3]=='t'){   //zestien

        }else if(regel[0]=='v' && regel[2]=='j' && regel[6]=='e'){   //vijftien

        }else if(regel[0]=='v' && regel[2]=='e' && regel[6]=='e'){   //veertien

        }else if(regel[0]=='d' && regel[2]=='r'){   //dertien

        }else if(regel[0]=='e' && regel[1]=='l'){   //elf

        }else if(regel[0]=='t' && regel[1]=='i'){   //tien

        }else if(regel[0]=='n' && regel[4]=='n' && regel[5]!='t'){   //negen

        }else if(regel[0]=='a' && regel[1]=='c' && regel[4]!='t'){   //acht

        }else if(regel[0]=='z' && regel[4]=='n' && regel[5]!='t'){   //zeven

        }else if(regel[0]=='z' && regel[2]=='s' && regel[5]!='t'){   //zes

        }else if(regel[0]=='v' && regel[3]=='f' && regel[5]!='t'){   //vijf

        }else if(regel[0]=='v' && regel[2]=='e'){                    //vier

        }else if(regel[0]=='d' && regel[1]=='r'){                    //drie

        }else if(regel[0]=='t' && regel[2]=='e'){                    //twee

        }else if(regel[0]=='e' && regel[1]=='e'){                    //een

        }else{

        }
    }

    printf("%s", out[0]);

    fclose (myFile);
    fclose (myFile1);

    return 0;
}

Thank you!

EDIT : I'm dutch, so all the full written words are Dutch.

Also, Twelve is missing, it's called twaalf in Dutch, in some kind of way that didn't work...

> myFile1 = fopen (argv[2], "r");
You should use "w" mode if you want to write to a file.

> if(regel[0]=='t' && regel[3]=='a')
Unless you can guarantee a minimum matching subset in all cases, you're probably going to find it easier if you begin with say
if ( strncmp(regel,"twintig",7) == 0 )


Perhaps a table of words, and a for loop, rather than an endless series of if / else if

Code:

char *words[] = {
    "twintig",
    "negentien",
    //etc
};