Thread: why does every character get printed twice?

I am working on a program that prints "How are you?" on the screen by printing byte by byte.

First I wrote

Code:

#include <stdio.h>
#include <stdlib.h>
int main()
{
       putchar(72);
       putchar(111);
       putchar(119);
       putchar(32);
       putchar(97);
       putchar(114);
       putchar(101);
       putchar(32);
       putchar(121);
       putchar(111);
       putchar(117);
       putchar(63);
   return 0;
}

And the output was exactly what was expected.

Now I wrote

Code:

#include <stdio.h>
#include <stdlib.h>
int main()
{
    unsigned char t[20];
    t[0]=72;
    t[1]=111;
    t[2]=119;
    t[3]=32;
    t[4]=97;
    t[5]=114;
    t[6]=101;
    t[7]=32;
    t[8]=121;
    t[9]=111;
    t[10]=117;
    t[11]=63;
    int i;
    for(i=0;i<12;i++)
        {
            printf("%c",putchar(t[i]));
        }
    return 0;
}

and the output is: HHooww aarree yyoouu??

Why?

EDIT:

I have it, there should be just the

Code:

    for(i=0;i<12;i++)
        {
            putchar(t[i]);
        }

> and the output is: HHooww aarree yyoouu??
> Why?
Because you're calling printf AND putchar at the same time.

Since putchar() returns the character printed, it also gets printed again though the %c format of printf.

Use one or the other.