Thread: IF Statement-- With curly brackets or semicolon

Hello,

I couldn't understand how does this "else" belong to inner "if" other than outer if when we dont use curly brackets or semicolon after outer if?

Code:

#include <stdio.h>

int main (void) {


	int x=4,y=2,z=3;
	if(x<y)
		if(x<z) 
			printf ("Minimum is x1 ");
		else 
			printf ("Minimum is z2 ");
	
	
	return 0;
}
//NO WRITTEN OUTPUT

Code:

#include <stdio.h>

int main (void) {


	int x=4,y=2,z=3;
	if(x<y);
		if(x<z) 
			printf ("Minimum is x1 ");
		else 
			printf ("Minimum is z2 ");
	
	
	return 0;
}
//OUTPUT: Minimum is z2

Code:

#include <stdio.h>

int main (void) {


	int x=4,y=2,z=3;
	if(x<y){
	
		if(x<z) 
			printf ("Minimum is x1 ");}
		else 
			printf ("Minimum is z2 ");
	
	
	return 0;
}
//OUTPUT: Minimum is z2

[/CODE]

Hi,
x is always smaller than y in your example.
First code : nothing wil happen because your first if returns false : the next if..else is not executed
Second code : no matter what the result of your first if because you finish its block with ";"

Code:

if(x<y);

. x is also not smaller than z so the answer is z2
Third example : the block between curly braces will not be executed because x is not smaller than y. Than comes the "else" block which is well executed

Hugues

Thank you both, but one point isnt clear yet for me.

If we dont ue semicolon or curly bracket after we use an "if statement" the first line after "if" belongs that "if". (1)

I used an "if" again. (2)

I wrote one line code belonging (2) .....(3)

I wanna write an "else statement" now next line. .....(4)

So, how can (4) belong to (2)?

Without curly braces "blocks", the else belong to the last if.
A rule I always use is to always make curly braces blocks, even for one line : it makes the code clear for anyone (included your compiler)

Okay, thank you GReaper and Bogdokhan for giving a time for the question, I got it. Have a goood day.