old failing brain

**jcfuller** · 12-31-2015

My c was not very good to begin with, but my old brain is failing me more and more lately.

Are these two the same?

Code:

char* ss ;
ss = GetInfo()
if(ss && ss[3]) == '2'


if (ss && ss[3]) == 50

James

**Salem** · 12-31-2015

They are, if you assume an ASCII character set.

**jcfuller** · 12-31-2015

Thank you!

James

**rstanley** · 12-31-2015

In addition to what @Salem said, "ss" should be pointing to a legitimate character array.

As written, ss is uninitialized.

I'm not sure what "GetInfo()" is.

Please provide a small but complete program that can be compiled and tested.

**jcfuller** · 12-31-2015

More code is irrelevant.
Salem gave the answer to the question asked.

James

**laserlight** · 12-31-2015

Hmm... but your code is syntactically incorrect to begin with. I don't see why you couldn't have written a program like this:

Code:

#include <stdio.h>

int main(void)
{
    printf("%d=50?\n", '2');
    return 0;
}

Then upon compiling it, running it, and seeing that the output was:

Code:

50=50?

ask if it was guaranteed that '2' == 50, upon which Salem's answer would apply.

**jcfuller** · 01-01-2016

Thanks guys I do appreciate the info but....
I am working on a new Basic -> c/c++ translator base on the original BCX.
There is no provision for parsing single quotes that are so prevalent in c code, as in the example.

I can use ASC("2") instead of '2' which mimics the c nomanclature and translates to 50.

So my Basic code is:

Code:

If ss AND ss[3] = ASC("2") Then
	'do your stuff
End If

And it translates to:

Code:

if(ss && ss[3]) == 50
{
	// do your stuff
}

James

**Salem** · 01-01-2016

> If ss AND ss[3] = ASC("2") Then

You could translate it to
if(ss && ss[3]) == "2"[0]

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