#define thing in C

[erdemtuna]

Hello,
Im novice in programming, i made a search on it but i couldnt understand why this code outputs 8?

#include <stdio.h>
#define Z 7 + 3
int main (void){
    
    int a = Z / 2;
     printf("%d", a);
}

[Salem]

$ gcc -E foo.c
<<< snipped a lot of expanded stdio.h
int main (void){

  int a = 7 + 3 / 2;
  printf("%d", a);
}

You see, your Z just expands to 7 + 3

Then operator precedence takes over.

[erdemtuna]

That's cool, so do not evaluate first like me Thank you a lot.

[laserlight]

Your takeaway here should actually be that parentheses should be used for such macros, e.g.,

#define Z (7 + 3)

though of course in this specific case you might just write:

#define Z 10