This program gives 2 2 2 as output but i don't get how? According to my understanding,
Initialization Cond Increment
0 true 1 so 1+2=3 should be printed then j=2-1=1 used
insertCode:#include<stdio.h> voidmain(){ inti,j=2; for(i=0;i<=5,j>=0;i++){ printf("%d ",i+j); j--; } }
And this program gives 2 2 2 2 2 . How does order in condition part affect output?
insertCode:#include<stdio.h> int main(){ inti,j=2; for(i=0;j>=0,i<=5;i++){ printf("%d ",i+j); j--; } return0; }
Note that void main should be int main, and consequently unless you are compiling with respect to C99 or later, you should return 0; at the end of the main function. Along with consistent indentation, formatting tweaks, and fixes to the markup by posting in plain text, your code would look like:
Code:#include<stdio.h> int main(void) { int i, j = 2; for (i = 0; i <= 5, j >= 0; i++) { printf("%d ", i + j); j--; } return 0; }The comma operator is in effect. In other words, this condition:Originally Posted by Izzy98
is equivalent to this condition:Code:i <= 5, j >= 0
Likewise this condition:Code:j >= 0
is equivalent to this condition:Code:j >= 0, i <= 5
because the left hand side operand of the comma expression is evaluated, then the right hand side operand of the comma expression is evaluated, and the result of the expression is the result of that right hand side operand.Code:i <= 5
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