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[erdemtuna]

I do not understand even if I wrote why this program doesnt print the total but does print the entered value?
Please explain me.

#include <stdio.h>
#include <math.h>

int main (void) {

int pronum; //this must be an integer, counter
float total;


scanf("%d",&pronum);

switch (pronum) {

case '1':
total = (pronum * 2.98);
break;

case '2':
total =( pronum* 4.50);
break;

case '3':
total = (pronum * 9.98);
break;

case '4':
total = (pronum * 4.49);
break;

case '5':
total = (pronum * 6.87);

break;



}


printf("%f\n%d",total,pronum);


return 0;
}

[sleax]

Because in the switch you have to use 1, not '1'

#include <stdio.h>
#include <math.h>


int main (void) {


	int pronum; //this must be an integer, counter
	float total;




	scanf("%d",&pronum);


	switch (pronum) {


		case 1:
			total = (pronum * 2.98);
			break;


		case 2:
			total =( pronum* 4.50);
			break;


		case 3:
			total = (pronum * 9.98);
			break;


		case 4:
			total = (pronum * 4.49);
			break;


		case 5:
			total = (pronum * 6.87);


			break;






	}




	printf("%f\n%d",total,pronum);




	return 0;
}

By using '1' you're testing if the value is the ASCII code of 1, that is 49.

[erdemtuna]

Oh,, so in numbers, we dont use '1' things. but if we want to indicate upper case or lower case letter, we can use?
Sorry Im novice, im trying to learn

[jimblumberg]

If you want to use letters you need to use a char, not an int.

Jim