Thread: Function returning pointer variable...

Code:

int *createFunction(int x);




int main(){
    int *foo = createFunction(35);
    
    printf("%d\n", *foo);
    
    return 0;
}


int *createFunction(int x){
    int *var;
    var = malloc(sizeof(int));
    
    *var = x;
    
    return var;
}

When I change the type of createFunction, 'int' to 'void', it works fine.

What's wrong with my code?

Code:

#include <stdio.h>
#include <stdlib.h>


typedef int gbType(int);
int *createFunction(int x);




int main(){
    gbType *foo = createFunction(35);
    
    printf("%d\n", *foo);
    
    free(foo);
    
    return 0;
}


int *createFunction(int x){
    int *var;
    var = malloc(sizeof(int));
    
    *var = x;
    
    return var;
}

Code:

test.c: In function 'main':
test.c:9:19: warning: initialization from incompatible pointer type [enabled by default]
     gbType *foo = createFunction(35);

Well it's not really an error...but why am I getting warning? and is there way to remove this warning?