Bitwise With If Else Statement

[naz1234]

what does this mean, this condition (z & (1 << 0)) ? ?

     

if (strstr(msg, "DO") == msg) //DO=0x[5]

{
       z = strtol(&msg[5], NULL, 16);//HEX
        LATGbits.LATG1 =  (z & (1 << 0)) ? 1 : 0; //lED1 , 0 OFF
        LATGbits.LATG0 =  (z & (1 << 1)) ? 0 : 1; //lED2 , 1 OFF
        LATGbits.LATG13 = (z & (1 << 2)) ? 0 : 1; //lED3 , 1 OFF
        LATGbits.LATG14 = (z & (1 << 3)) ? 0 : 1; //lED4 , 1 OFF
        LATGbits.LATG12 = (z & (1 << 4)) ? 0 : 1; //lED5 , 1 OFF
        sendString("OK\r\n"); //REPLY OK
}

[jimblumberg]

Also posted here.

[GReaper]

"<<" is the bit-shift-to-the-left operator. Here's a wikipedia link
"&" is the bitwise-and operator. Here's almost the same wikipedia link
"?" is the ternary operator. Here's another link

EDIT: LOL, the other thread is linking this one.

[naz1234]

LOL, so jimblumberg is a Skydiver? .