Thread: Page Fault in Visual C++

GOT IT!
try this
note: scanf you forgot the & (address of)

Code:

#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main()

	{

	char array[100], exp[100], id[10], num[10], digit[10], letter[10];
	int i=0, j=0;

	printf("Please enter an expression: ");
	scanf("%s", exp);

	printf("%s\n", exp);

	if (exp[i] == '(')
		array[i] = 20;
	else if(exp[i] == ')')
		array[i] = 21;
	else if(exp[i] == '+')
		array[i] = 16;
	else if(exp[i] == '-')
		array[i] = 17;
	else if(exp[i] == '*')
		array[i] = 18;
	else if(exp[i] == '/')
		array[i] = 19;

	else if(isdigit(exp[i]))
		while(isdigit(exp[i])){
			*digit = exp[i];
			*num = strcat(num, digit);
				++i;}
		else if(isalpha(exp[i]))
			while(isalpha(exp[i])){
				*letter = exp[i];
				*id = strcat(id, letter);
				++i;}
	else
		printf("%c is invalid\n", exp[i]);

for(j=1; j<100; j++)
	{
	printf("%c\n",array[j]);
}


}

note: ' ' is for character comparison
" " is for string comparison...

-Luke

try this
note: scanf you forgot the & (address of)

Well, U need not specify the & (address of) operator for arrays and pointers (because, when u specify the variable name of an array, its base address is automatically referenced.

code:--------------------------------------------------------------------------------
#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main()

{

char array[100], exp[100], id[10], num[10], digit[10], letter[10];
int i=0, j=0;

printf("Please enter an expression: ");
scanf("%s", exp);

printf("%s\n", exp);

if (exp[i] == '(')
array[i] = 20;
else if(exp[i] == ')')
array[i] = 21;
else if(exp[i] == '+')
array[i] = 16;
else if(exp[i] == '-')
array[i] = 17;
else if(exp[i] == '*')
array[i] = 18;
else if(exp[i] == '/')
array[i] = 19;

else if(isdigit(exp[i]))
while(isdigit(exp[i])){
*digit = exp[i];
*num = strcat(num, digit);
++i;}
else if(isalpha(exp[i]))
while(isalpha(exp[i])){
*letter = exp[i];
*id = strcat(id, letter);
++i;}
else
printf("%c is invalid\n", exp[i]);

for(j=1; j<100; j++)
{
printf("%c\n",array[j]);
}


}

*letter=exp[i] etc.... Do they really work. U declared them as arrays not pointers.

Then...

note: ' ' is for character comparison
" " is for string comparison...

I've not seen direct string comparision in C. Use strcmp instead (defined in string.h)


-Harsha.

Yes it works....I myself said that when ever an array is referred, its base address is passed...

Did the page fault problem come to an end now, reader?? Can

char array[100], exp[100], id[10], num[10], digit[10], letter[10];
int i=0, j=0;

printf("Please enter an expression: ");
scanf("%s", exp);

be a problem...I mean, what if the entered expression is more than 100 chars. So, scanf can be re-written as...

scanf("%100s",exp);

Check it out.

-harsha.