I understand that the sizeof(short_int)=2 bytes, sizeof(int)=4 bytes, sizeof(long_int)=8 bytes but what I mean to ask is if it is the case that int can store a digit up to 10^M, short int up to 10^L & long int up to 10^N where L<M<N? Is it the case?
If my understanding is correct then how can I know about these limits of storage i.e. L,M,N? If not then what is the real thing?
The sizes of the integral types have implementation defined minimums and maximums which are defined in the <limits.h> include file.
Jim
In the case of Microsoft compilers, int and long int are both 4 bytes (32 bits) and long long int is 8 bytes (64 bits).
Note that this is not necessarily true. The relevant rule is that sizeof(char) == 1, sizeof(char) <= sizeof(short) <= sizeof(int) <= sizeof(long) <= sizeof(long long), where I use <= with pseudo-mathematical syntax. Related to this is the rule that CHAR_BIT is at least 8. Of course, the minimum guaranteed ranges as mentioned by jimblumberg must still hold for the implementation to conform to the standard.Originally Posted by smrtshrm
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