Thread: Help with basic C syntax

What is the value of expression *(p+i) in function f() in the following code:

Code:

#include<stdio.h>
    float m[4][4]={{1.5,2.5,3.5},{3,4.5,5.5},{5,6.5,7.5}};
    
void f(float *p, int m, int n)
{
int i, b1=0, b2, s=0;
for (i=m, b2=b1; i<=n; s+=*p, i++)
if (*(p+i))
b1++;
else
++b2;
printf("%d %d %d %f", b1, b2, s,p[i]);
}

int main()
{
f(&m[1][2],1,9);
return 0;
}

When I debugged the code, after first if-else statement, if statement is passed and else is executed.
So, how the value of *(p+i) is 0?

Thanks for replies.

So, how the value of *(p+i) is 0?

That's because

Code:

float m[4][4]={{1.5, 2.5, 3.5},{3, 4.5, 5.5}, {5, 6.5, 7.5}};

is the same as

float m[4][4]={{1.5, 2.5, 3.5, 0.0}, {3, 4.5, 5.5, 0.0},{5, 6.5, 7.5, 0.0}, {0.0, 0.0, 0.0, 0.0,}};

Remember, all the values you don't give an initial value in your array are set to 0;

Cheers