Thread: how to get hex values as output without conversion

Hi
I have written a code,in which i have hard coded hex values to a array (a[5]).I need these hex values which i have given to this array as ouput.On compiling the code,i am getting the converted values of these hex to int (e.g. 0x001 =1,0x002 = 2,0x0a4 = 164).

How can i get the given hex values as output without the conversion taking place?

Code:

#include <stdio.h>


int main(void) {
    int i;
     unsigned char a[5]={0x0a4,0x002,0x003,0x004};
    unsigned char p[i];
    for(i=0;i<4;i++)
    {
        p[i]=a[i];
    //    printf("%c",p[0]);
  //  memcpy(p[i],a[i],strlen(a[i]+1));
    
    printf("\n%d",p[i]);
    }
    //return 0;
}

pls help?!

Originally Posted by bharockz

Hi
I have written a code,in which i have hard coded hex values to a array (a[5]).I need these hex values which i have given to this array as ouput.On compiling the code,i am getting the converted values of these hex to int (e.g. 0x001 =1,0x002 = 2,0x0a4 = 164).

How can i get the given hex values as output without the conversion taking place?

Code:

#include <stdio.h>


int main(void) {
    int i;
     unsigned char a[5]={0x0a4,0x002,0x003,0x004};
    unsigned char p[i];
    for(i=0;i<4;i++)
    {
        p[i]=a[i];
    //    printf("%c",p[0]);
  //  memcpy(p[i],a[i],strlen(a[i]+1));
    
    printf("\n%d",p[i]);
    }
    //return 0;
}

pls help?!

Some errors to fix first
1. In line 7, i is not initialized and should be changed to 5
2. In line 5, though the value is fine but I think you should ommit one zero thus from 0x0a4 to 0xa4 since your array is of type character and is only one byte but 0x0a4 is 2 bytes but is still ok since the zero is irrelevant

So the code in line 7 is not required anymore.
The above solution is correct you can use "0x%02x" or "0x%03x" instead or "%d"

Thank you guys!!!