Thread: Passing Values between Functions

Hello,

In the below code after returned the value of "d", is it goes to int calsum (int x, int y, int z); or sum = calsum (a, b, c); .

I have a lot of confusion to understand which steps code will takes after value returned from the return statement. Please explain.

Code:

#include <stdio.h>
int calsum (int x, int y, int z);
int main()
{
int a, b, c, sum;
printf ("Enter any three numbers");
scanf ("%d %d %d", &a, &b, &c);
printf ("Sum = %d\n", sum);
return 0;
}
int calsum (int x, int y, int z)
{
int d;
d=x+y+z;
return (d);
}

Code:

#include <stdio.h>
int calsum (int x, int y, int z);
int main(void)
{
int a, b, c;

printf ("Enter any three numbers");
scanf ("%d %d %d", &a, &b, &c);
printf ("Sum = %d\n", calsum(x,y,z));

return 0;
}
int calsum (int x, int y, int z)
{
return x+y+z;
}

As laserlight said you did not call calsum. But now you call it. In addition you need no d variable only the return statement to return your sum.The result of the function will be printed from printf function and that's all.

Code:

 int calsum(int x, int y , int z);

is only a declaration of the funtion in order to help the compiler to check the call later.

The values goes to the call. After the call the value of the function is returned to the caller function if it has a value and return type of course. In other case the function will do the calculation (whatever it is) and the flow of the program will be continued to the point of the call.The program will continue to the next statement after this call.

Thank you.