Thread: if statement with 2 conditions

Hi all,
I am currently trying to learn C and would appreciate any help...

Can anyone please explain why the following code will not work?
The if statement if (yn!='y' || yn!='n') always becomes true!

Code:

#include<stdio.h>

main()
{
    char yn;
    while(yn!='e') {
        printf("enter y/n? ");
        scanf(" %c", &yn);
            if (yn=='e') {
                printf("goodbye\n");
                break;
            }        

            if (yn!='y' || yn!='n') {
                printf("error, enter y or n!\n");
            }
    }
return 0;
}

I did manage to replicate the code with nested if's but after much reading it's better to write more concise code. Correct me if I am wrong?

Code:

#include<stdio.h>

main()
{
    char yn;
    while(yn!='e') {
        printf("enter y/n? ");
        scanf(" %c", &yn);
            if (yn=='e') {
                printf("goodbye\n");
                break;
            }            

            if (yn!='y') {
                if (yn!='n') {
                    printf("error, enter y or n!\n");
                }
            }
    }
return 0;
}