Thread: how to call a function that takes a STRUCT parameter

I just want to call the function : outputboo(), but I dont know how

Code:

/*Enthusiastic
Pessimism
desensitize
uniqueness
*/

#include <stdio.h>
#include <string.h>

struct Books{
   char  title[50];
   char  author[50];
   char  subject[100];
   int   book_id;
};
struct Books printhello();
int  outputboo(struct Books boo);

int main( ){

printhello();
int outputboo();

}

    int outputboo(struct Books boo){
    printf(" here is your value of the function of the STRUCT :%i",&boo.book_id );

}

      struct Books printhello(){
      struct Books boo ;
      printf("Enter your book # here please :");
      scanf("%i",&boo.book_id);
      printf("your boo book_id is : %i\n\n\n\n\n\n\n\n\n\n", boo.book_id);
      ;
}

Originally Posted by laserlight

You really need to indent your code properly. For example:

Code:

/* Enthusiastic
   Pessimism
   desensitize
   uniqueness
*/
 
#include <stdio.h>
#include <string.h>

struct Books {
    char  title[50];
    char  author[50];
    char  subject[100];
    int   book_id;
};

struct Books printhello();
int outputboo(struct Books boo);

int main() {
    printhello();
    int outputboo();
}

int outputboo(struct Books boo) {
    printf(" here is your value of the function of the STRUCT :%i",&boo.book_id );
}

struct Books printhello() {
    struct Books boo;
    printf("Enter your book # here please :");
    scanf("%i", &boo.book_id);
    printf("your boo book_id is : %i\n\n\n\n\n\n\n\n\n\n", boo.book_id);
    ;
}

As for your problem, I suggest the use of a pointer, e.g.,

Code:

void print_book(const struct Books *book) {
    printf(" here is your value of the function of the STRUCT :%i", book->book_id);
}

Now you can call it:

Code:

struct Books book;
book.book_id = 123;
print_book(&book);

sorry for the confusion I caused by not indenting my Code