Thread: Dynamic array from Function to Function

Your compiler has to be warning you about an invalid call to ArrayScan() (if it's not, it's broken, and you should get a new compiler).

You're passing &array to ArrayScan(). array has type int*, so &array has type int**. However, ArrayScan() expects an int*. int** and int* are incompatible types.

Passing &array is right, because you need ArrayScan() to modify array (you need it to make array point somewhere). But that means that ArrayScan() needs to take int** instead of int*; and each time you use "h" in the function, you should be using "*h". Since h points to an int*, *h is an int*, which is to say *h is the same thing as "array" in your main function.

This is no different than passing, say, an int* to a function when it needs to modify the int. Instead, you're just passing an int** so the function can modify the int*.

Thank you very much for the response, cas. I tried to change my code (wrote int **, instead of int *, changed to *h in functions). However, it doesn't compile me.
What am i doing wrong now?

Code:

#include <stdio.h>#include <stdlib.h>
void ArrayScan(int n, int **h);
void ArrayMaximum(int n, int *h, int x);
int main()
{
    int n, *array;
    int max = 0;




    printf("Write the number of random numbers: ");
    scanf("%d", &n);
    ArrayScan(n,&array);
    ArrayMaximum(n,array, max);
    free(array);
    getch();
}
void ArrayScan(int n, int **h)
{
 int i = 0;
 h = (int*)malloc(n* sizeof(int));
 for ( ; i<n; i++)
 scanf("%d", *(h+i));
}
void ArrayMaximum(int n, int *h, int x)
{
 int i=0;
 x = *(h+i);
 for( ;i<n;i++)
 {
  if (*(h+i)>x)
  x = *(h+i);
 };
 printf("The maximum is: %d", x);
}