Thread: Printing the value of a pointer

Hello,I'm trying to print the full value (in hexadecimal) of a pointer.This is my best attempt so far:

Code:

char *text = "\x10\x11\x12\x13\x14\x15\x16\x17";printf("%x", &text);

And it obviously doesn't work, best I've gotten is a single byte, but I want the whole lot of bytes.Any ideas?Thanks for your time!

Originally Posted by sockets12

Hello,I'm trying to print the full value (in hexadecimal) of a pointer.This is my best attempt so far:

Code:

char *text = "\x10\x11\x12\x13\x14\x15\x16\x17";printf("%x", &text);

And it obviously doesn't work, best I've gotten is a single byte, but I want the whole lot of bytes.Any ideas?Thanks for your time!

are you trying to print address where that pointer is or where it points or what it points? make it clear...

Originally Posted by grumpy

In this case, I think the problem description is flawed, and %p is not the solution.If the intent is to produce an output "1011121314151617" (without the quotes) then it is necessary to print every character of text individually using %x. However, describing that as "printing the full value of a pointer" is incorrect.

Thanks! Doing a for loop and printing from there worked perfectly.