The error message is this:
test.c(9):warning *** 'auto' variable 'n' may be used before initialization at test.c(8)
My code is this:
Can you see anything in this code that would cause the compiler to generate the above error message?Code:1 #include <gb/gb.h> 2 #include <stdio.h> 3 4 void main() 5 { 6 int n; 7 while(1) { 8 printf("%d\n",n); 9 n++; 10 } 11 }
Last edited by Videogamer555; 09-26-2014 at 03:26 PM.
You attempt to print (and afterward increment) the value 'n' before it is given a value (and it is not initialized to anything).
The warning told you so explicitly.
Also: FAQ > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[]) - Cprogramming.com
As I'm most familiar with Visual Basic, which always initializes numerical variables to 0 at the moment they are defined ("dim n as long in" VB is the same as "int n;" in C) so I was not aware that in C I would need a separate line like "n=0;" after the "int n;". I assumed that most programing languages automatically caused any variable to be equal to zero at the instant that the variable was defined.Originally Posted by Matticus
I found the following topic after a quick search - the top answer might give you some insight: c - why global variables are always initialized to '0', but not local variables? - Stack Overflow
However, don't be tempted to declare your variables globally for this effect!
And you don't need a separate line of code to initialize 'n' - just do:
Code:int n = 0;
You assumed wrong. Most programming languages do not require initialisation of non-static variables. VB is one of the exceptions in this case, not C.
You should assign a value to the variable you defined. If you don't do this in the C programming language, you get an error while you are trying to print the variable you defined without assigning an initial value.
