Char to Hex

[orion314]

I'm trying to write a program that takes input from the user (thats a char) and outputs it to the
monitor in hex form.The program is meant to continuously take input from the user then output to the monitor in hex form until an EOF is detected this triggers the program to close.The following code does this except that I get a lower case 'a' at the end of each output.I think the 'a' has to do with the enter key and if that is the case how can i tell the program to ignore this input from the user. I am noob at programming please help me or at least point me in the right direction.
Thank you.
example:

input from user: ABC
output to monitor: 41 42 43 a

#include <stdio.h>


int main(void)
{
    char myChar;
    
    while(EOF != (myChar = getchar()))
    {
              printf("%x ",myChar);
                  
    }
    
  system("pause");
  return 0;


}

[c99tutorial]

Yes, you are correct that pressing ENTER is seen by getchar, this character is called the newline character and is written as '\n' in C. You could use an if statement to ignore this character from your printout. For example,

while(EOF != (myChar = getchar()))
{
    /* don't convert newline into hex */
    if (myChar == '\n')
        continue;

    printf("%x ",myChar);
}

[orion314]

Thank you so much I could kiss you. I have been on this bug for a couple of hours.
One question though does the continue in the code tell the program that if it sees \n
then to just ignore it and move on?

[c99tutorial]

One question though does the continue in the code tell the program that if it sees \n
then to just ignore it and move on?

That's right. continue says to go to the next loop iteration. Another variation of this would be the following which does not use continue. However notice that this version will stop the loop as soon as a newline is encountered. That may be what you want, or maybe not.

while((myChar = getchar()) != EOF && myChar != '\n')
{
    printf("%x ",myChar);
}
printf("\n");

[laserlight]

Personally, I suggest avoiding the use of continue, but rather let control fall to the end of the loop body and loop back up again, e.g.,

while (EOF != (myChar = getchar()))
{
    /* convert into hex, except for newlines */
    if (myChar != '\n')
    {
        printf("%x ", myChar);
    }
}

[Salem]

Char To Hexadecimal, Hexadecimal Back To Char - C And C++ | Dream.In.Code