Thread: strdup() and execvp()

I am working on an intro to OS book and have some questions about this code:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <sys/wait.h>


int main(int argc, char *argv[]) {
     printf("hello world (pid:%d)\n", (int) getpid());
     int rc = fork();
     if (rc < 0) { // fork failed
          fprintf(stderr, "fork failed\n");
          exit(1);
     } else if (rc == 0) { // child (new process)
          printf("hello, I am child (pid:%d)\n", (int) getpid());
          char *myargs[3];
          myargs[0] = strdup("wc"); // program: "wc" (word count)
          myargs[1] = strdup("p3.c"); // argument: file to count
          myargs[2] = NULL; // marks end of array
          execvp(myargs[0], myargs); // runs word count
          printf("this shouldn’t print out");
     } else {              // parent goes down this path (main)
          int wc = wait(NULL);
          printf("hello, I am parent of %d (wc:%d) (pid:%d)\n",
                  rc, wc, (int) getpid());
     }


     return 0;
}

Because I am using strdup() to create this new strings, shouldn't I be free()ing the pointers? Or does execvp() somehow handle this?

The book says the heap and stack and other parts of the memory space of the program are reinitialized. I know that these pointers reside in the heap, but what does it mean to be "reinitialized"?

Thank you.