C program

[NiÂz]

Hi can you plz explain me the below program :
#include <stdio.h>
#include <stdlib.h>

int main()
{
int a=6,b=4;
int c=a+b;
printf("%d",c);
return 0;
}
Out put >> 10

I f i scan the input's like below i get variable answers on every debug why so
#include <stdio.h>
#include <stdlib.h>

int main()
{
int a,b;
int c=a+b;
scanf("%d%d",&a,&b);
printf("%d",c);
return 0;
}

i.e, if i give i/p as 6 & 4 i get output as : 4341809 sometimes 8732171 its varies >>> check my output online too > C code - 11 lines - codepad

[Matticus]

In C, values are calculated as they are encountered during code execution.

"c=a+b" does not set up a formula that automatically updates the value of 'c' whenever 'a' and 'b' change values.

Instead, the line "c=a+b" calculates the sum once. At that point, 'a' and 'b' aren't initialized, or given meaningful values, so they contain random values. These random values are added and stored into 'c'.

So you have to move the "c=a+b" line after 'a' and 'b' are given values.

[Alpo]

If I understand you correctly, I think the problem is that you are assigning c before values are stored in a or b. Try declaring c first, and moving the assignment below scanf.

[deysourav]

use c = a+b; only if and b has the values that you want store in it.

[NiÂz]

Awesome understanding..got your point thanQ so much

[NiÂz]

Ya i knew that but still i wan to know why this happens..Thanx for your reply got my answer

[NiÂz]

ThanQ