Thread: Day of the Week Programme

Hi everybody,

Here I come again. I feel so stuck... I'm faced with a coding exercise, the solution to which, I'm unable to find even after trying to break my head onto the wall....

The problem is that this is more of a beginner's exercise and as such I'm allowed to only use if statements!

Following is the thing:-

Q. According to the Gregorian calendar, it was Monday on the date 01/01/01. If any year is input through the keyboard, write a program to find out what is the day on 1st of January of the year input.

And, below is some scribbling that I tried. But, my head seems to go blank after that...

Code:

/* Determination of Day on 01-01 */

#include<stdio.h>

int main()
{
  int year, Day;
  
  printf("\nEnter a Year: ");
  scanf("%d",&year);
  
  Day = /* Doomsday Algorithm, maybe... or Zeller's Congruence... aaah... forget it...*/

}

Thanks in Advance for your help.

January 1, 2001 = Monday.
So in 2002 it would be?
add 365 days - which is like adding exactly 52 weeks + 1 day. 52 x 7 + 1 = 365.
So the weekday slips ahead one day from Monday to Tuesday.
Then for 2003 the weekday would slip ahead again to Wednesday.
Then for 2004 the weekday would slip ahead again to Thursday.
For 2005 ... but 2004 is a leap year, so slip ahead 2 days to Saturday.
So now you need to figure out what's a leap year.
Now you also have to consider what happens if the input year is before 2001.

This is how you solve things. Do several examples by hand.

Yeah. That's my problem...! I'm unable to be able to figure out the algorithm.... I'll try this by doing some examples by hand.I guess I'm just too impatient...

Originally Posted by Anish Kuriakose

I guess I'm just too impatient...

i'm so sorry