Thread: Why the following code not working?

Code:

#include <stdio.h>
#include <stdlib.h>


void magicsq(int **ar,int n);
int main()
{
    int n;
    printf("enter size");
    scanf("%d",&n);
    int a[n][n];
    int i=0,j=0;
    for(i=0;i<n;i++)
    {
        for(j=0;j<n;j++)
        {
            a[i][j]=0;
        }
    }
    magicsq(a,n);


    return 0;
}
void magicsq(int **ar,int n)
{
    printf(ar[1][1],"\n");
    int i=0,j=0,k=1,previ,prevj;
   while(k<=(n*n))
   {
       if(k==1)
       {
       ar[0][n/2]=k;
       printf("dd");
       }
       else
    {
        printf("\ndd");
      previ=i;
      prevj=j;
      if((i-1)>=0 && (j-1)>=0)
      {
          i=i-1;
          j=j-1;
      }
      else if((i-1)==-1 && (j-1)>=0)
      {
          i=n-1;
          j=j-1;
      }
      else if((i-1)==-1 && (j-1)==-1)
      {
          i=n-1;
          j=n-1;
      }
      else if((i-1)>=0 && (j-1)==-1)
      {
          i=i-1;
          j=n-1;
      }
    if(!ar[i][j])
    {
        ar[i][j]=k;
        printf("\n",ar[i][j]);
    }
    else
    {
        if((previ+1)<n)
        {
            i=previ+1;
            ar[i][j]=k;
            printf("\n",ar[i][j]);
        }
        else
        {
            i=0;
            ar[i][j]=k;
            printf("\n",ar[i][j]);
        }
    }}
    k++;
    }
     for(i=0;i<n;i++)
    {
        printf("\n");
        for(j=0;j<n;j++)
        {
            printf("\t",ar[i][j]);


        }
    }//printf("dd");
    }

On running this code it gives error:Program not responding.
I guess there is some problem with the passing of array to function.