Thread: how to assign a string into a cell of an array

What do you mean "Into the cell of an array"?

Do you want an array of strings? Otherwise, a "cell" of your array only contains a single character. If you want the "cell" to contain a whole string, you need an array of character pointers. Then you need to actually get into dynamicly allocating space and what not. Not that difficult, but it can be tricky.

Quzah.

I don't know about VB, but I think your problem is you are using a character when you need a string and vice-versa.

arrayName[0] = a single character(the first letter)

arrayName = string(actually a pointer to the array of chars that make up the string.)

Try this:

Code:

char arrayName[20]; 
printf("enter name:   "); 
gets(arrayName); 
printf("\n%s", arrayname);

I didn't have a compiler to check this, but I think it is right.

If you really want to use scanf() instead of gets(), try:

Code:

scanf("%s", arrayName);

It looks like you want a two dimensional array or an array of pointers:

Code:

char a[2][20];
fgets ( a[0], sizeof a[0], stdin );
printf ( "%s", a[0] );

Code:

char *a[2];
if ( ( a[0] = malloc ( 20 * sizeof *a ) ) != NULL ) {
  fgets ( a[0], 20, stdin );
  printf ( "%s", a[0] );
}

-Prelude