Thread: passing char array index as pointer

Hi I am trying to write a light weight printf style function.

I have got this far:

Code:

void println(const char *txData){
	LOG(__PRETTY_FUNCTION__);
	UARTPuts (LPC_UART0, txData);
}
void miniPrint(const char *format, ...)
{
	unsigned int index = 0;
	va_list argptr;

	va_start(argptr, format);

	while(format[index] != '\0')
	{
		if(format[index] == '%')
		{
			index++;

			if(format[index] == '\0')
				break;

			switch(format[index])
			{
				case 'd':
					send_int(va_arg(argptr, uint32_t));
					break;
				case 'c':
					transmit(va_arg(argptr, uint32_t));
					break;
				case 's':
					sendString(va_arg(argptr, char *));
					break;
				default:
					println(&format[index]);
			}
		}
		else {
			println(&format[index]);
		}

		index++;
	}

    va_end(argptr);
}

(its for an embedded platform)

If I do:

Code:

miniPrint("hello\n");

in main, I get:

hello
ello
llo
lo
o

I understand why I think. When I am passing the reference to the array possion it is outputting everything up to the next /0. So my question is how do I stop it?

I dont have much choice as to how the output wants it:

Code:

void UARTPuts(LPC_UART_TypeDef *UARTx, const void *str)

Thats library code, so I dont want to change it. I.e I have to pass an address into println.

Thanks
Alex