Thread: find word and insert another word after that in text

Hi,
I have text (string) and I want to find a given word (it's ok!) and then insert another given word after the first word.
The original string is beeing copied into a new string.
But something is going wrong!!!

Where is my mistake?

Thanks in advance...

(I have some patches...)

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//insert "new_word" after each occurence of "word"
int main(){
char A[100]="In the sentence words the and the.";
char B[200]="";
char *word="the";
char *new_word="com";
char *p;
int word_count=0;
int i,j,word_index;
int found,position;

i=0;
j=0;
found=0;

while(A[i]!='\0'){
   word_index=0;
   position=i;
   while(A[i]==word[word_index]){//we found same letters
      B[j]=A[i];//copy A to B letter by letter
      printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);//getchar();
      i++;j++;word_index++;//increment indices
      printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);//getchar();
      printf("A: %s\n",A);
      printf("B: %s\n",B);
   }
   if (word_index==strlen(word)) {//word was found
       found=1;
       printf("position=%d\n",position);
       printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);//getchar();
       B[j]=' ';
       j++;
       strcat(B,new_word);//copy new_word to B[] after word
       printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);//getchar();
       printf("A: %s\n",A);
       printf("B: %s\n",B);
       j=j+strlen(new_word)+1;//increment j
       B[j]=' ';
       printf("A: %s\n",A);
        printf("B: %s\n",B);
       i++;j++;
       continue;//exit while loop and continue parsing
   }
   else{
        B[j]=A[i];//else continue copying A to B
        printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);//getchar();
        printf("A: %s\n",A);
        printf("B: %s\n",B);
        i++;j++;
        }
}
if(!found) printf("\"%s\" not found!\n",word);
puts(A);
puts(B);
getchar();

return 0;
}

Originally Posted by c99tutorial

Do you want to insert the new word or replace the old word? In other words, what is the expected ending values for A and B in your example?

We find "the" and after each occurence of "the" we add the word "com".
output:
A: (the same)
B:"In the com sentence words the com and the com."

thanks in advance..

Originally Posted by c99tutorial

If you insert "com" after every instance of "the", then shouldn't the result be like this:

B: "In thecom sentence words thecom and thecom."

Where does the extra space come from?

I mean that "com" is a new word..the word "the" remains the same...

Yes, I agree with you...
But my program doesn't work properly....where is my mistake??

ok! I fixed it!
I made it with pointers, whose, IMO, are better implementation for manipulating a C string...
I'm expecting your comments....

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//insert "new_word" after each occurence of "word"
int main(){
char A[100]="in the the";
char B[200]="";
char *word="the";
char *new_word="com";
char *a,*b,*w,*nw;
int word_count=0;
int i,j,word_index;
int found,position;

a=A;
b=B;
w=word;
nw=new_word;
found=0;

while(*a!='\0'){
	w=word;
   //position=i;
   while(*a==*w&& *a!='\0'){//we found same letters
      *b=*a;//copy A to B letter by letter
      //printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);getchar();
      a++;b++;w++;//increment indices
      //printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);getchar();
   }
   if (*w=='\0') {//word was found
       found=1;
       //printf("position=%d\n",position);
       //printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);getchar();
       *b=' ';
       b++;
       strcat(B,new_word);//copy new_word to B[] after word
       //printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);getchar();
       b=b+strlen(new_word);//increment j
       *b=' ';
       a++;b++;
       continue;
   }
   else{//we are here, that means *a!=*w, word dont match...
        *b=*a;//else continue copying A to B
        //printf("A[%d]=%c B[%d]=%c \n",i,A[i],j,B[j]);getchar();
        a++;b++;
        }
}
if(!found) printf("\"%s\" not found!\n",word);
puts(A);
puts(B);
getchar();
   
return 0;   
}