Thread: "simple" login authorization code

get_info.user_ID
get_info.pass_word
get_info.first_name
get_info.last_name
get_info.user_flag

If you try to count those, and only manage to count to 1, I think we've got other problems here.

How else would you explain the line

Code:

sscanf(buffer,"%[^,], %[^,], %[^,], %[^,], %[^,]", get_info.user_ID, get_info.pass_word, get_info.first_name, get_info.last_name, get_info.user_flag) == 1

?

sscanf(buffer,"%[^,], %[^,], %[^,], %[^,], %[^,]", get_info.user_ID, get_info.pass_word, get_info.first_name, get_info.last_name, get_info.user_flag) == 1

sscanf: is reading within the file by line

buffer: is the entire file

"%[^,], %[^,], %[^,], %[^,], %[^,]": is reading comma separated data and skipping commas

get_info.user_ID, get_info.pass_word, get_info.first_name, get_info.last_name, get_info.user_flag: is the memory place holders for the infomation

== 1: 1 for true, 0 for false.

this is how i see it.

Then you should get your glasses on and read the manual for sscanf, specifically about the value it returns (which isn't true/false, but the number of items read).

i know i'm trying to do what "http://911programming.wordpress.com/2010/05/15/sample-c-io-student-recods/" is doing.

You can't use "%[^,], %[^,], %[^,]" as the format, because that's not the format that the data is in. Have you read the manual yet? You may want to explore what * can do for you.

i do have C the complete reference 4th edition, but it's vague or moot on what i'm trying to do here.

there is a bit more online:
Sample C I/O: Student Records | 911 programming

but again not really what i'm trying to do.

it's seems as if nobody is doing it this way.

is there another direction i should be taking???

So there is such a thing as the manual. Why not read it?

Originally Posted by jkgoose937

it's one thing to read text it's another to understand what the text means.

Well, no; that's kinda what "reading" means. I mean, let's look at the bit in the manual about *:

Originally Posted by linux scanf manual

An optional '*' assignment-suppression character: scanf() reads input as directed by the conversion specification, but discards the input. No corresponding pointer argument is required, and this specification is not included in the count of successful assignments returned by scanf().

That seems fairly straightforward to me: if you put a * in the conversion, scanf reads the input as the format would normally indicate, but doesn't actually try to store that information anywhere. You also don't have to include an argument for it in your inputs.

If you have six items on a line (making up a record), you've got to indicate that in your format string -- the format string must match the input format, that's why it's there. If you don't care about three of those fields, then you can use a * to indicate that those values shouldn't be stored. But you can't leave them out of the format.

so if i'm understanding:

a: sscanf(buffer,"%[^,], %[^,], %[^,]", get_info.user_ID, get_info.pass_word, get_info.user_flag, *, *, *,) == 3);
or
b: sscanf(buffer,"%[^,], %[^,], %[^,], *, *, *", get_info.user_ID, get_info.pass_word, get_info.user_flag, *, *, *,) == 3);

How about

Code:

sscanf(buffer, "%[^,], %[^,], %*[^,], %*[^,], %*[^,], %[^,]", get_info.user_ID, get_info.pass_word, get_info.user_flag)

assuming I have remembered which fields were where in the file.

Why does it take 12 posts to finally get somewhere?

I have been more than upfront about my lack of understanding here.

I have lost all respect and faith in this forum.

People here may be skilled in programming but lack in teaching skills.

I really had hopes to one day to contribute to the Linux community and became a programmer.

It's not about giving up per se, but rather knowing that for first time students your better of beating your head against the wall.

I'm not going to apologize for my frustrations here, that would go against everything I believe,
but I hope it's a warning to others that wish to get help, know programming first.

I'm done.