Thread: Processing outputs of multiple inputs

It's not something trivial but I would like to know the best way to process multiple outputs, for example:

Input
First line of input will contain a number T = number of test cases. Following lines will contain a string each.

Output
For each string, print on a single line, "UNIQUE" - if the characters are all unique, else print "NOT UNIQUE"

Sample Input
3
DELHI
london
#include<iostream>

Sample Output
UNIQUE
NOT UNIQUE
NOT UNIQUE


So how can I accomplish outputs like that? My code so far is:

Code:

int main(int argc, char *argv[]) 
{

     int inputs, count=0;
     char str[100];
     char *ptr;

     scanf("%d",&inputs);


     while(inputs-- >0)
     {
         scanf("%s",str);

         for(ptr=str; *ptr!='\0';ptr++)
         {
             if( *ptr== *(ptr+1))
             {
                 count++;
             }
         }
         if(count>0)
         {
             printf("NOT UNIQUE");

         }
         else
         {
             printf("UNIQUE");
         }

     }

}

But the above will obviously print the output after each input, so I want to know how can I achieve the result given in the problem. Also another thing I want to know is, I am using an array of 100 char, which it can hold a string up to 100 characters, but what do I have to do if I want to handle string with no limit? Just declaring char *str is no good, so what to do?

Originally Posted by dotnet13

It's not something trivial but I would like to know the best way to process multiple outputs, for example:

Input
First line of input will contain a number T = number of test cases. Following lines will contain a string each.

Output
For each string, print on a single line, "UNIQUE" - if the characters are all unique, else print "NOT UNIQUE"

Sample Input
3
DELHI
london
#include<iostream>

Sample Output
UNIQUE
NOT UNIQUE
NOT UNIQUE


So how can I accomplish outputs like that? My code so far is:

Code:

int main(int argc, char *argv[]) 
{

     int inputs, count=0;
     char str[100];
     char *ptr;

     scanf("%d",&inputs);


     while(inputs-- >0)
     {
         scanf("%s",str);

         for(ptr=str; *ptr!='\0';ptr++)
         {
             if( *ptr== *(ptr+1))
             {
                 count++;
             }
         }
         if(count>0)
         {
             printf("NOT UNIQUE");

         }
         else
         {
             printf("UNIQUE");
         }

     }

}

But the above will obviously print the output after each input, so I want to know how can I achieve the result given in the problem. Also another thing I want to know is, I am using an array of 100 char, which it can hold a string up to 100 characters, but what do I have to do if I want to handle string with no limit? Just declaring char *str is no good, so what to do?

Take first character in the string then compare with all 2 to n characters. likewise you can check for 2nd with 3 to n and so on. If u find duplicate character in between then print "NOT UNIQUE" and return.
This may not be the best solution, but it will work. It will take too much time if the string length is very big and there are no duplicate characters or those exist at the end.

return in the sense stop checking that string and take another string as input. No need to check a string if we find a duplicate character.