Thread: Why does this statement print a 0?

Code:

#include <stdio.h>

main ()
{
printf(" %x", !0xabababababab );
}

This prints out a 0 and I'm not sure why. Any insight? Thanks!

0x is a prefix for hexadecimal numbers.
a,b are valid hex digits, so it is a number which is not 0.

To expand on manasij7479's comment:

Code:

non-zero value == true
zero value == false

!(non-zero value) == !(true)  == false == 0
!(zero value)     == !(false) == true  == 1

And to add to that, if you were trying to do bitwise NOT, that's ~.