Thread: Floyd triangle - hint plz

Code:

/* Shown below is an Floyd's triangle*/
1
2 3
4 5 6
7 8 9 10
11 .... 15
..
..
79 ......... 91
/* Give me the idea to generate this, thankq */

Welcome to the forum. Please post your attempt to solve this problem. Or, lacking an attempt, tell us what ideas you have thought of so far.

Here also: Idea please - C++ Forum

Code:

#include <stdio.h>


int main()
{
	int i, j, num = 1;
	
	for (i = 1; i <= 91; i++)
	{
		for (j = 1; j <= i; j++)
		{
			printf("%d ", num);
			num++;
			if (num == 92)
				break;
		}
		
		printf("\n");
		if (num == 92)
			break;
	}
	
	return 0;
		
}

Stop insulting other.

You don't know what an insult actually is, but we'll stop "insulting" when you decide to post in one forum.

Not quite...here's my solution:

Code:

#include <stdio.h>

void printFloyd(int size);

int main(void)
{
    printFloyd(91);
    return 0;
}

void printFloyd(int size)
{
    int num, cols, cols_per_row;

    cols_per_row = 1; /* # columns to start out with */
    for (num = 1, cols = 0; num <= size; ++num) {
        printf("%3d ", num);
        ++cols; /* # columns in this row so far */

        /* Did we hit our column limit for this row? */
        if (cols >= cols_per_row) {
            printf("\n");
            cols = 0;           /* New row, so reset column count */
            cols_per_row++;     /* Next row has +1 more columns */
        }
    }
}

Hodor you're missing some logic in yours (as well as the i in your printf() statement)

Originally Posted by nonpuz

Hodor you're missing some logic in yours (as well as the i in your printf() statement)

Yeah, I typed it straight into the website and then realised I should have checked it first =)

Code:

#include <stdio.h>

int main(void)
{
    int i = 0, c = 0, m = 0, n = 91;
    static const char delim[] = {' ', '\n'};

    while (i < n) {
        printf("%d%c", i + 1, delim[c == m]);
        if (c == m)
            c = 0, m++;
        else
            c++;
        i++;
    }
    return 0;
}

What do you want that bit of code to do? The comma operator just discards the thing on the left, so the 0 is completely ignored. If you want some sort of if statement, then maybe you're looking for ?: ?

Well since we are all producing solutions now:

Code:

>>> def floyd(rowcount = 5):
...     return [ list(range(i*(i-1)//2+1, i*(i+1)//2+1)) for i in range(1, rowcount+1) ]
...
>>> floyd()
[[1], [2, 3], [4, 5, 6], [7, 8, 9, 10], [11, 12, 13, 14, 15]]
>>>

That seems to be the hard part.

Originally Posted by laserlight

If your intention is to write:

Code:

c = 0;
m++;

Then just write that instead of trying to be unnecessarily concise and making it difficult to understand for both yourself and those who read your code.

I had no itention of writing that at all; I was merely trying to make sense of your earlier comment. Hmm

In effect, c = 0, m++; is c = m++; the assignment to zero may as well have never happened.