Thread: string array question if I get it?

Hi,
this is my code:

Code:

#include <stdio.h>

int main(){
        
    char message[12];

    printf("Hit me with max. 10 hits!");
    fgets(message, 12, stdin);

    printf("What you hitted:\n%s", message);

    return 0;
}

I have read that an array of string also includes \0 and \n and I also read that fgets adds an \n.
So is my idea in the table right?

index	0	1	2	3	4	5	6	7	8	9	10	11	12
value	1	2	3	4	5	6	7	8	9	0	\n	\0	\n

I am looking forward to hear from you.

King regards,
Greenality

\0 must be present at the end. \n can be present in the string, just as with any other character. Input from fgets may have an \n at the end, depending on how many characters the user typed.

A string is just a character array with a terminating character ('\0') at the end.

Code:

// explicitly initialize each element of the array
char array_1[6] = {'H', 'e', 'l', 'l', 'o', '\0' };

// initialize the array with a string literal (the compiler will automatically
// add the null character, but it's up to the programmer to leave enough space
// for it in the array!
char array_2[6] = "Hello";

"fgets()" reads in a string and terminates it, but it has the caveat of also storing the newline if there is room.

So to correct your example:

Code:

index  0 1 2 3 4 5 6 7 8 9 10 11
value  1 2 3 4 5 6 7 8 9 0 \n \0

Note that, in my correction, index only goes up to 11. That is because the valid range of "array[n]" is from zero to "n-1".

Ok, thank you for your help and for your really quick answers. :-) Thanks.