I am to make a program that uses function pointers to give an output of adding numbers together or taking the average of these three numbers. I have almost most of it figured out, but am running into a problem. I am supposed to print out also which option they choose, but when I put a print statement into the function, it prints that statement out twice. I'm assuming because the first time it goes to that function and prints it out, then when I call that function in the print statement in main, it prints it out again. I'm not sure. Any advice would be appreciated. Thank you.
Code:#include <stdio.h> int addFunct(int num1, int num2, int num3); int averageFunct(int num1, int num2, int num3); int main() { int num1 , num2, num3, option; int (*f[2])(int num1, int num2, int num3) = {addFunct, averageFunct}; printf("Please enter a number greater than 0 to start.\nEnter a negative number to quit.\n"); printf("Please enter the first number.\n"); while (num1 >= 0) { scanf("%d", &num1); printf("Please enter the second number.\n"); scanf("%d", &num2); printf("Please enter the third number.\n"); scanf("%d", &num3); printf("What would you like to do? Please pick the appropriate number.\n"); scanf("%d", &option); if (option >= 0 && option < 2) (*f[option])(num1, num2, num3); printf("The answer is %d", f[option](num1, num2, num3)); printf("Please enter the first number.\n"); scanf("%d", &num1); } return 0; } int addFunct(int num1, int num2, int num3) { int add = 0; printf("You have chosen to add the two numbers.\n" ); add = num1 + num2 + num3; return add; } int averageFunct(int num1, int num2, int num3) { int average = 0; printf("You have chosen to average the three numbers.\n"); average = (num1 + num2 + num3) / 3; return average; }
