Thread: Divide fail

Well ever other operator works instead of divide works. When I add multiply or subtract I get the correct results but when I divide I get some answer that aint numbers, works or even english.

Code:

	else if(check == '/')
	{
		printf("Enter the first number.\n");
		scanf("%d", &num1);
		fflush(stdin);
		printf("Enter the second number.\n");
		scanf("%d", &num2);
		fflush(stdin);
		
		printf("The answer is: %f", num1 / num2);
	}

num1 and num2 are both integers so the result of the division is an int too. "%f" expects a float
Kurt

so If I added a variable and saved it in it would be printed as a float?

Try printf("%f", (float)a / (float)b);

Originally Posted by rcgldr

Try printf("%f", (float)a / (float)b);

You don't have to explicitly promote both a and b

Originally Posted by bos1234

Paste your full code so we can highlight the mistake for you. As mentioned above, it may be due to the fflush or the way you have declared your variables.

Code:

#include <stdio.h>

int main()
{
    int a = 6, b = 5;

    printf("%f", a/b);

    getchar();
    return 0;

}

I have declared a and b as int, but am trying to print a float. Do you have it something similar to the above?

look at the first post

Originally Posted by BIGDENIRO

look at the first post

And rc answered... try printf("%f\n", (float)a/b);

Originally Posted by rcgldr

Try printf("%f", (float)a / (float)b);

Originally Posted by SirPrattlepod

You don't have to explicitly promote both a and b

True, but it might help the original poster understand the issue better rather than relying on promotion of "b" to a float because "a" was cast to a float.