Thread: If statement wont check the second condition

I've tried retyping the code several times and didn't work for some reason the If wont accept both Q and q it just accepts Q.

Code:

#include <stdio.h>
int main(void)
{
	printf("A menu will show up and you choose the number for the selection you want.\n\n");
	system("pause");
	//here should get the letter entered
	printf("Press the menu key \"q\" or \"Q\" to open the menu.\n\n");
	
	//here is to check if the letter is Q or q
	if (getchar() == 'Q' || getchar() == 'q')
	{
		printf("\t\tMod Menu");
	}
	else
	{
		printf("Didn't enter \"Q\" or \"q\".\n");
	}
	return 0;
}

I did try saving it as a variable but I keep getting warning messages that says something like trying to match string with integer set by default?

The code was ALOT different than this, I saved it over with the new in the first post and I just wrote this to show you the message I was getting:

Code:

#include <stdio.h>


int main(void)
{
	char menu[1];
	
	printf("A menu will show up and you choose the number for the selection you want.\n\n");
	system("pause");
	//here should get the letter entered
	printf("Press the menu key \"q\" or \"Q\" to open the menu.\n\n");
	scanf("%c", &menu);
	//here is to check if the letter is Q or q
	if (menu == 'Q' || menu == 'q')
	{
		printf("\t\tMod Menu");
	}
	else
	{
		printf("Didn't enter \"Q\" or \"q\".\n");
	}
	return 0;
}

13 11 C:\Dev-Cpp\My Codes\Simple mod menu.c [Warning] comparison between pointer and integer [enabled by default]
13 26 C:\Dev-Cpp\My Codes\Simple mod menu.c [Warning] comparison between pointer and integer [enabled by default]

Originally Posted by Salem

Use a single char, not an array of char (not even a char array with only one element).

Well, you could use a char array with only one element but it'd be a bit silly.

Took Salem advice and it works now.

by the way why u using system("pause"); ?