Multiple scanf not reading input

[Lilith Matthews]

Hello,

my program is supposed to take 2 numbers separated by a comma and then run them through a loop to determine the GCD, but every time I run the program the scanf isn't reading the inputs and just keeps displaying white space like I haven't entered anything. It won't execute the code after scanf.

Here's the code snippet.

int user1;
int user2;
int GCDcheck;
printf ("Enter the two (non-zero) integers: ");
scanf ("%d,%d", &user1, &user2);
GCDcheck = user1 * user2;

it never executes the GCDcheck = user1 * user2;

I've looked around and can't find something similar to this problem, any help or any insight would be greatly appreciated.

[Adak]

Welcome to the forum, Lillith!

I tried your code in this little snippet of a program, and it prints them out properly. Are you entering the comma and a space between the two integers?

#include <stdio.h>

int main(void) {

   int user1;
   int user2;
   int GCDcheck;
   printf ("Enter the two (non-zero) integers: ");
   scanf ("%d,%d", &user1, &user2);
   printf("user1: %d   user2: %d \n",user1,user2);
   GCDcheck = user1 * user2;


   return 0;
}

[Lilith Matthews]

Yes, I am. I thought that I was coding it correctly. What could be causing it to not work? This is so frustrating!

[Adak]

This snippet also works for me.

#include <stdio.h>

int main(void) {

   char comma;
   int user1;
   int user2;
   int GCDcheck;
   printf ("Enter the two (non-zero) integers: ");
   scanf ("%d%c %d", &user1,&comma, &user2);
   printf("user1: %d   user2: %d \n",user1,user2);
   GCDcheck = user1 * user2;

   return 0;
}

Usually, it's a good idea to leave comma's out of the scanf() format string.

[vart]

It would help if you show the exact input (by copying in whole cmd line output into the post together with code)

For example using code from post #2 I got the following

Enter the two (non-zero) integers: 4,5
user1: 4   user2: 5
Press any key to continue . . .