Thread: Counting the number of case selections in a menu

There's a similar question to this below me, but I thought it would be easier to answer if there was an example to refer to.

Code:

  #include<stdio.h>

int main () {
    int choice, opens, saves, news;

    printf("What would you like to do?\n");
    printf("\t1 - Open\n");
    printf("\t2 - Save\n");
    printf("\t3 - New\n");
    printf("\t4 - Display selections\n");

    scanf("%d", &choice);

while (choice != 4){
   switch(choice) {
        case 1:
            printf("Opening..");
            break;

        case 2:
            printf("Saving..");
            break;

        case 3:
            printf("Creating new..");
            break;

        case 4:
            break;           

        default:
            printf("Invalid Input.");
            break;
   
 } //switch close


    printf("What would you like to do?\n");
    printf("\t1 - Open\n");
    printf("\t2 - Save\n");
    printf("\t3 - New\n");
    printf("\t4 - Display selections\n");
    scanf("%d", &choice);


} //while close

printf(" %d opens, %d saves, %d new files", opens, saves, news);

 return 0;
}

So what would I have to add in order for this code to display how many times the user has selected open, save or new? I'd really appreciate the help.

Thank you grumpy! I feel silly now, I can't believe didn't realize how simple it was. I got it working now