Thread: I am trying to create a very simple program but running into difficulty

I am only just learning this. I am trying to create a program in my own way instead of doing exactly what the tutorial says. What I am trying to do is print only a remainder of a simple division if the program divides a value by itself and the number isn't 1. Maybe you can follow my code. Haha sry if its tough to follow it I am very new to this:

Code:

#include <stdio.h>
#include <math.h>

#define YARDS_PER_SWEATER 460
#define YARDS_PER_HAT 220

int main(void) {
    
    int num_balls, yards_per_ball;
    int num_h, num_s;
    float yards_left;
    
    printf("How many balls of yarn do you have?\n");
    scanf("%d" , &num_balls);
    
    printf("How many yards are in each of your balls of yarn?\n");
    scanf("%d" , &yards_per_ball);
    
    num_h = (num_balls*yards_per_ball)/(YARDS_PER_HAT);
    num_s = (num_balls*yards_per_ball)/(YARDS_PER_SWEATER);
    
    if ((num_h||num_s)/(num_h||num_s) != 1)
    
    printf("You have some yarn left over after you make %d sweaters or %d hats for other projects,\nif you want to know how many yards you have, type 'yes' below.\n" , num_s, num_h);
    scanf("%d%d%d" , &Y, &E, &S);
    
    yards_left = num_h
    
    
    
    else if ((num_h||num_s)/(num_h||num_s) == 1))
    
    print("You can make %d sweaters or %d hats, but you have no yarn left over.")
    
    getchar();
    return 0;
}

My first suggestion is for you to review your documentation for the if() statement. Here is a good tutorial on the subject.

Also do you understand that when doing integer math there are no fractions, 1/5 will yield zero.

Jim

Originally Posted by oogabooga

I'm stymied, man.
Unless it's zero, a number divided by itself is always 1.
Can you describe your assignment?

Yea, I dont know what I was thinking at the time hahaha. What I want to do is basically tell the program

if num_h or num_s has a remainder, I want to only display the number of hats with the remaining yards left over.. Still struggling to make that happen.spelling

Then you should be looking into using the modulus operator %, remember there are no fractions with integers, just whole numbers.


Jim

Originally Posted by jimblumberg

Then you should be looking into using the modulus operator %, remember there are no fractions with integers, just whole numbers.


Jim

I looked at it and it threw me for a loop. I dont know what that cin >> means.. All I want to do is do that calculation for num_hats and show a remainder

Ok I got it to go further without errors but not compiled yet. After reading about the modulus and seeing oogabooga's post, this is what I have now

Code:

#include <stdio.h>
#include <math.h>

#define YARDS_PER_SWEATER 460
#define YARDS_PER_HAT 220

int main(void) {
    
    int num_balls, yards_per_ball;
    float num_h, num_s;
    float yards_left;
    
    printf("How many balls of yarn do you have?\n");
    scanf("%d" , &num_balls);
    
    printf("How many yards are in each of your balls of yarn?\n");
    scanf("%d" , &yards_per_ball);
    
    num_h = (num_balls*yards_per_ball)/(YARDS_PER_HAT);
    num_s = (num_balls*yards_per_ball)/(YARDS_PER_SWEATER);
    yards_left = total_yards % (YARDS_PER_HAT || YARDS_PER_SWEATER);
    
    if (yards_left > 0)
    
       printf("You have some yarn left over after you make %lf sweaters or %lf hats for other projects,\nif you want to know how many yards you have, type 'yes' below.\n" , num_s, num_h);
       scanf("%d%d%d" , &Y, &E, &S);
    
    else
    
        print("You can make %lf sweaters or %lf hats, but you have no yarn left over.");
    
    getchar();
    return 0;
}

Ok, this is what I have now, but I am getting an error at the yards_left calculation

Code:

#include <stdio.h>
#include <math.h>

#define YARDS_PER_SWEATER 460
#define YARDS_PER_HAT 220

int main(void) {
    
    int num_balls, yards_per_ball;
    int num_h, num_s;
    float yards_left, yards_left1, total_yards;
    
    
    
    printf("How many balls of yarn do you have?\n");
    scanf("%d" , &num_balls);
    
    printf("How many yards are in each of your balls of yarn?\n");
    scanf("%d" , &yards_per_ball);
    
    
    total_yards = (num_balls*yards_per_ball);
    num_h = (total_yards)/(YARDS_PER_HAT);
    num_s = (total_yards)/(YARDS_PER_SWEATER);
    yards_left = total_yards % (YARDS_PER_HAT || YARDS_PER_SWEATER);
    
    
    
    if (yards_left > 0)
    
       printf("You have %lf yards of  yarn left over after you make %d sweaters"
              "or %d hats.\n" , yards_left, num_s, num_h);
              
    
    else
    
       print("You can make %d sweaters or %d hats with no yarn left over.");
    
    getchar();
    return 0;
}