Thread: Trying to add a little extra to a "Switch Statement" assignment.

I pretty much got the assignment done. All it asked for was that you make a C program that displays which manufacturer owned a disk drive based on the code entered. Pretty simple. Just enter 1, 2, 3, or 4 and get the associated manufacturer. Though I am trying to implement an error messege to it for any interger that isn't 1-4.

Code:

#include <stdio.h>

int main()
{

int code;

printf("Please enter the Disk Drives code: ");
scanf("%d", &code);

switch (code)
{

    case 1:
        printf("The code entered was %d and the associated manufacturer is 3M Corporation", code);
        break;
    case 2:
        printf("The code entered was %d and the associated manufacturer is Maxwell Corporation", code);
        break;
    case 3:
        printf("The code entered was %d and the associated manufacturer is Sony Corporation", code);
        break;
    case 4:
        if (code = 4)
            printf("The code entered was %d and the associated manufacturer is Verbatim Corporation", code);
        else
            printf("The code entered was %d and is not related to any corporation.", code);
        break;
}

return 0;
}

I also tried this, but it didn't work either.

Code:

    case 4:
        if (code < 1 || code > 4)
            printf("The code entered was %d and is not related to any corporation.", code);
        else
            printf("The code entered was %d and the associated manufacturer is Sony Corporation", code);
        break;
}

No errors are given and it works fine as long as you enter 1-4, but when you enter any other didgit it just stops the program without any messeges.

Thanks!

Ahh, didn't think about using the default case. The ex. programs didn't use default at all lol. I had to dig back through the chapter to see it mentioned. lol

using the default case worked though 100%. Thank you!

Code:

#include <stdio.h>

int main()
{

int code;

printf("Please enter the Disk Drives code: ");
scanf("%d", &code);

switch (code)
{

    case 1:
        printf("The code entered was %d and the associated manufacturer is 3M Corporation", code);
        break;
    case 2:
        printf("The code entered was %d and the associated manufacturer is Maxwell Corporation", code);
        break;
    case 3:
        printf("The code entered was %d and the associated manufacturer is Sony Corporation", code);
        break;
    case 4:
        printf("The code entered was %d and the associated manufacturer is Verbatim Corporation", code);
        break;
    default:
        printf("The code entered was %d and is not related to any corporation.", code);
        break;
}

return 0;
}

Had to use this to see an example of it. Pretty ironic.

This is my favorite way to handle such tasks.

Code:

static const char *mfg[] = {
    "(none)", "3M Corporation", "Maxwell Corporation",
    "Sony Corporation", "Verbatim Corporation"
};

printf("The code entered was %d and the associated manufacturer is %s\n",
       code, code < sizeof(mfg)/sizeof(mfg[0]) ? mfg[code] : mfg[0]);

BTW, I would declare code to be unsigned to avoid a problem with a negative number.

Originally Posted by KenJackson

This is my favorite way to handle such tasks.

I guess the assignment's purpose was to practice the switch statement ;-).

Bye, Andreas