Character Counting Program. Crashes at the End.

[psukphranee]

So I am writing a program that counts the letters of 3 lines of input from the user. I am using a 3 x 80 character array as the "notepad".
Upper and lower case characters are incremented on the same counter array.

/*Letters in a string*/
#include <stdio.h>
#include <string.h>
#include <ctype.h>

void countAlphabet(char *);

/*Character counting array*/
int alphabet[26] = {0};

int main(void){

    char paper[3][80];
    
    int counter = 0;

    char c;

    printf("Enter 3 lines of texts\n");

    fgets(paper[0], 80, stdin);
    fgets(paper[1], 80, stdin);
    fgets(paper[2], 80, stdin);

  
    for(counter = 0; counter < 3; counter++)
        countAlphabet(&paper[counter]);

    for(counter = 0; counter <26; counter++)
        printf("%d ", alphabet[counter]);

    printf("\n");


    return 0;
}


void countAlphabet(char *line){

    int i = 0;

    printf("Inside countAlphabet\n");
    while(i< 80){

        if((line[i] <= 122 && line[i] >= 97) || (line[i] >= 65 && line[i] <= 90)){
            if(isupper(line[i]))
                ++alphabet[line[i] - 97];
            else
                ++alphabet[line[i] - 26];
        }
        
        i++;
    }
}

[Salem]

> if((line[i] <= 122 && line[i] >= 97) || (line[i] >= 65 && line[i] <= 90))
There is another is... function to do this (see your use of isupper on the next line.

> ++alphabet[line[i] - 26];
Where did 26 come from?

Perhaps you should use
++alphabet[line[i] - 'A'];
and/or
++alphabet[line[i] - 'a'];
as appropriate

[ZuK]

countAlphabet(&paper[counter]);

increase the warning level of your compiler.
Kurt

[psukphranee]

Responding to second >,

I did some scratchwork where i printed the character and integer value of those statements and they come out fine