Need help With c Progam

[craff25]

My computer just crashed and I lost my files, I have this program due tomorrow, if anyone could solve and show the code that'd be great.

Problem below:------------------------------------------------

Write a function, named sums(), that has two input parameters; an array, called Input of doubles; and an integer which is the number of values stored in the array. Compute the sum of the positive values in the array and the sum of the negative values. Also count the number of values in each category. Return these four answers through output parameters. Write a main program that reads no more than 10 real numbers and stores them in an array. Stop reading numbers when a 0 is entered. Call the sums() function and print the answers it returns. Also compute and print the average values of the positive and negative sets. Align decimal points on numbers
SAMPLE INPUT:
-123.45
-234.56
576.1
-9.345
675.2
100
-10
1654.45
765.89
0 (NOT in computation)
SAMPLE OUTPUT:
YourName Program#1 CS110
Input Read:
9999.9999
9999.9999
...

Statistics:
Desc Number Total: Average:
Positive 99 99999.9999 9999.9999
Negative 99 99999.9999 9999.9999
Overall 99 99999.9999 9999.9999

[Adak]

Fortunately, you have some time. Start it off -- and post it up, ASAP.

[Click_here]

My computer just crashed and I lost my files...

Sounds legit - We better do their homework for them!

[Barney McGrew]

My computer just crashed and I lost my files

So forget about the program for now and focus on recovering your files.
TestDisk - CGSecurity

[Click_here]

Or better yet ->

Dear Professor Foo -

My computer has just crashed and I've lost my file for project Banana.

My program took three days to complete, so I was hoping that I'd be able to get a 3 day extention to recomplete it.

Kind regards,
Student Foo.

[craff25]

Fortunately, you have some time. Start it off -- and post it up, ASAP.

sorry thought I added it, here is what I got

[craff25]

#include <stdio.h>
 
void sums(double Input[], int elements, double *PSum, double *NSum, int *numOfP, int *numOfN);
 
int main()
{
    double Input[10];
    double PSum = 0, NSum = 0, userInput; //positive and negative sum
    int numOfP = 0, numOfN = 0; //number of postive and negatives
    int i;
    for(i = 0; i < 10; i++){
          printf("Enter a real number or '0' to stop: ");
          scanf( " %lf", &userInput);
          if(userInput == 0){
              break;
          }
          Input[i] = userInput;
    }
    sums(Input, i, &PSum, &NSum, &numOfP, &numOfN);
    printf("Sum of positives: %.2f\nNumber of positives: %d\n", PSum, numOfP);
    printf("Sum of negatives: %.2f\nNumber of negatives: %d\n", NSum, numOfN);
    printf("Average of positives: %.2f\n", PSum / numOfP);
    printf("Average of negatives: %.2f\n", NSum / numOfN);
 
    return 0;
    
}
 
 
void sums(double Input[], int elements, double *PSum, double *NSum, int *numOfP, int *numOfN)
{
     int i;
     for(i = 0; i < elements; i++){
           if(Input[i] > 0){
                       *numOfP += 1;
                       *PSum += Input[i];
           }
           else{
                       *numOfN += 1;
                       *NSum += Input[i];
           }
     }
}

[laserlight]

Post your code in [code][/code] bbcode tags. Do not add any syntax highlighting of your own.

I have edited your post for you.

[craff25]

Sounds legit - We better do their homework for them!

I apologize i thought i added the code didnt realize you needed to actually write in [code] on post i have uploaded what I've done so far

[craff25]

Post your code in [code][/code] bbcode tags. Do not add any syntax highlighting of your own.

I have edited your post for you.

I think thats right sorry im new to all this lol

[Adak]

I understand this to mean the sum() function can only have two input parameters - you have several pointers extra. Please explain.

Write a function, named sums(), that has two input parameters; an array, called Input of doubles; and an integer which is the number of values stored in the array.

If the function returned the count of positive numbers, then you could calculate the count of negative numbers, using subtraction, in main() correct?

[craff25]

I understand this to mean the sum() function can only have two input parameters - you have several pointers extra. Please explain.



If the function returned the count of positive numbers, then you could calculate the count of negative numbers, using subtraction, in main() correct?

yes i believe so

[Adak]

One way to do what you need to do, is to use a static variable, in sum(). In this case, a static variable of a struct, which you describe above main() (so that description is in global space, and any function can use it.

I'm not sure this works OK, or not, and I'm not sure you can use a static variable or not.

#include <stdio.h>
  

typedef struct stats{
   int posCount;
   int negCount;
   double posSum;
   double negSum;
}stats;

stats sums(double Input[], int elements);
  
int main()
{
   double Input[10];
   double userInput; //positive and negative sum
   stats stat;
   int i;
   for(i = 0; i < 10; i++){
      printf("Enter a real number or '0' to stop: ");
      scanf( " %lf", &userInput);
      if(userInput == 0){
         break;
      }
      Input[i] = userInput;
   }
   stat=sums(Input, i);
   printf("Sum of positives: %.2f\nNumber of positives: %d\n", stat.posSum,stat.posCount);
   printf("Sum of negatives: %.2f\nNumber of negatives: %d\n", stat.negSum,stat.negCount);
   printf("Average of positives: %.2f\n", (double)stat.posSum / i);
   printf("Average of negatives: %.2f\n", (double)stat.negSum / i);
  
   return 0;
}
stats sums(double Input[], int elements)
{
   int i;
   static stats stat1;
  
   for(i = 0; i < elements; i++){
     if(Input[i] > 0){
         stat1.posCount += 1;
         stat1.posSum += Input[i];
     }
     else{
         stat1.negCount += 1;
         stat1.negSum -= Input[i];
     }
   }
   return stat1;
}

[AndiPersti]

I understand this to mean the sum() function can only have two input parameters - you have several pointers extra. Please explain.

The description in post #1 says that there should be 2 input parameters and 4 output parameters, thus the approach using the pointers is correct IMHO.

@craff25ff: What's your problem? The program in post #7 basically works (not sure about the output format; what about the possible division by zero?).

Bye, Andreas

[Adak]

The description in post #1 says that there should be 2 input parameters and 4 output parameters, thus the approach using the pointers is correct IMHO.

@craff25ff: What's your problem? The program in post #7 basically works (not sure about the output format; what about the possible division by zero?).

Bye, Andreas

Explain to me if you would about this "input parameter" versus "output parameters", because I'm confused.

I would classify everything in the parameter list as input, and only the return from the function, being output.

Especially confusing is saying the array "pointer" (almost) is an input parameter, but several other pointers are all output parameters, even though they are receiving new input, inside the function??

Is there a reference to this in K&R, someplace?