Preforming operations on an array

[Joie Moie]

For my assignment I have to have an array with only zeros.

int a[20] = { 0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0 };

Then I need to send it into a function that makes the array like this

int a[20] = {0,1,2,3,4,5,6, ... , 19}

Which I have done here

int initialize(int a[], int n)

{
    int m = 0;
    int i;
    
    printf("\n");
    printf("Now the array is \n");
    
           
    for (i=0; i<20; i++ )
    {   
        
        a[i] = a[i] + m;
        
        m = m + 1 ;
        
        printf ("%3d", a[i]);
        
        }
        
        
}

Now I need to do the following with the array.

I need to take whatever value is in each position and add that value to all of the previous values.

like this.

a[3] = a[3] + a[2] + a[1] + a[0]

only for every a[i]

I know that I can code this the long way, but I just can't see to be able to find out how to do this a better way.

Thanks.

by the way its my first post.

[rcgldr]

For the first one you could have just done:

   for (i=0; i<20; i++ )
        a[i] = i;

For the next one, you'll need to use a nested loop (a loop within a loop).