Thread: C Program that output the very next date after Input a date

It's my second week of learning C programming. So, don't laugh at me . I have figured out the algorithm of the problem, but after coding it's not working. Would you please tell me where's the problem?

Code:

#include<stdio.h>
int main()
{
    int d, m, y, nd, nm, ny;
    printf("Enter the year: ");
    scanf("%d", &y);
    printf("\nEnter the month: ");
    scanf("%d", &m);
    printf("\nEnter the date: ");
    scanf("%d", &d);
    printf("\nSo, your desired date is: %d/%d/%d", d, m, y);
    if (m%2!=0 && m<=7)
    {
        if (d==31)
        {
            nd=1;
            nm=m+1;
            ny=y;
        }
    }
    else if (m%2==0 && 8<=m<=12)
    {
        if (d==31)
        {
            nd=1;
            nm=m+1;
            ny=y;
        }
    }
    else if (m%2==0 && 4<=m<=6)
    {
        if (d==30)
        {
            nd=1;
            nm=m=1;
            ny=y;
        }
    }
    else if (m%2!=0 && 9<=m<=11)
    {
        if (d==30)
        {
            nd=1;
            nm=m+1;
            ny=y;
        }
    }
    else if (m==2 && y%4==0)
    {
        if (d==29)
        {
            nd=1;
            nm=m+1;
            ny=y;
        }
    }
    else if (m==2 && y%4!=0)
    {
        if (d==28)
        {
            nd=1;
            nm=m+1;
            ny=y;
        }
    }
    else if (m==12 && d==31)
    {
        nd=1;
        nm=1;
        ny=y+1;
    }
    else
    {
        nd=d+1;
        nm=m;
        ny=y;
    }
    printf("\n\nThe next date of your desired date is:\t%d/%d/%d\n", nm, nm, ny);
}

Originally Posted by stahta01

Can you tell us what the problem is?

Edit1: The below code does NOT do what you think it does!

Code:

8<=m<=12

Likely want

Code:

(8<=m && m<=12)

Tim S.

Thank you for your help . The problem is: "C Program that output the very next date after Input a date" According to your comment I changed the program a little bit. But still not working

Code:

#include<stdio.h>int main()
{
    int d, m, y, nd, nm, ny;
    printf("Enter the year: ");
    scanf("%d", &y);
    printf("\nEnter the month: ");
    scanf("%d", &m);
    printf("\nEnter the date: ");
    scanf("%d", &d);
    printf("\nSo, your desired date is: %d/%d/%d", d, m, y);
    if (m%2!=0 && m>=1 && m<=7 && d==31)
    {
        nd=1;
        nm=m+1;
        ny=y;
    }
    else if (m%2==0 && m>=8 && m<=12 && d==31)
    {
        nd=1;
        nm=m+1;
        ny=y;
    }
    else if (m%2==0 && m>=4 && m<=6 && d==30)
    {
        nd=1;
        nm=m=1;
        ny=y;
    }
    else if (m%2!=0 && m>=9 && m<=11 && d==30)
    {
        nd=1;
        nm=m+1;
        ny=y;
    }
    else if (m==2 && y%4==0 && d==29)
    {
        nd=1;
        nm=m+1;
        ny=y;
    }
    else if (m==2 && y%4!=0, d==28)
    {
        nd=1;
        nm=m+1;
        ny=y;
    }
    else if (m==12 && d==31)
    {
        nd=1;
        nm=1;
        ny=y+1;
    }
    else
    {
        nd=d+1;
        nm=m;
        ny=y;
    }
    printf("\n\nThe next date of your desired date is:\t%d/%d/%d\n", nm, nm, ny);
}

Why isn't it working?


Jim

Why are you playing with the month in most of your if statements. You should first just add one to the day, if that is less than 29 you should be done, after all, all months have at least 28 days.

Also in your last print statement you seem to be printing the month twice, don't you want to print the day?

Code:

  printf("\n\nThe next date of your desired date is:\t%d/%d/%d\n", nm, nm, ny);

Jim

Thanks Jims. Now works. You are the man