Thread: Code not functioning properly

I just started learning C, so please bear with my if my code is not all that great! So I am basically trying to print out "Start Typing >" utilizing lc4_puts(). Then I am trying to fall into a loop where it waits for me to type a character and then prints that character to the console. The program terminates when it encounters a line feed character char '/n'. My code is compiling, but not giving the desired result. "Start Typing >" prints to the screen, but I cannot type after that.

Code:

#include "os_trap_wrappers.h"

// set the size of the character array input
#define STRING_SIZE 100 


int main(void)
{
	char c, input[STRING_SIZE];
	int i;


lc4_puts("Start Typing >");
for (i = 0; (c = lc4_getc()) != '\n'; ++i) {
	input[i] = c;




}


input[i] = '\0';
lc4_putc(input[i]);
return 0;
}

and this is my os wrapper code

Code:

 char lc4_getc();void lc4_putc(char c);
void lc4_puts(char *str); 
void lc4_draw_box(int x, int y, int size, int *colors);

any help would be greatly appreciated!

In addition to what GReaper asked, note this:

Code:

input[i] = '\0';
lc4_putc(input[i]);

You're setting the last position of "input" to '\0' which is okay, but then you're only trying to print a single character - specifically, the '\0' you just put in that location. If you're intending to print out the entire string entered, this is not the way to do it.

The macros getc() and putc() are used to read characters from the keyboard and to print characters on the screen, respectively.

thanks!