Thread: function call to print the smallest number?

C programming, make it use a function call to print the smallest number?

hi guys
this is a program which prints out the smallest of three numbers within
the main function that I was asked to write.
Now the other question i am asked,5. Re-write the program, uses a function call to print the smallest number?
what do it mean if someone can explain or show me an example please
i am new to c

Code:

# include <stdio.h>

main()
{
int a,b,c;
int temp, min;

a = 100;
b = 23;
c = 5;

min = a;
temp = b;
if (min < temp)
{
min = temp;
temp = c;
if (min < temp)
{
min = temp;
printf (“\nThe minimum value of these three numbers is ”, min);
}
else 
{
printf (“\nThe minimum value of these three numbers is “, min);
}
}
else
{
temp = c;
f (min < temp)
{
min = temp;
printf (“\nThe minimum value of these three numbers is ”, min);
}
else 
{
printf (“\nThe minimum value of these three numbers is “, min);
}
}

It's kind of difficult to give an example of this without just giving away the answer. Start by writing a function that receives the numbers declared in "main()", and move the relevant code into that function.

Based on the assignment, you should have already learned about functions, so refer to your notes for reference. You can also find information here:

Functions in C - Cprogramming.com

Line #6, what are you missing -- look in the format section.

Code:

printf("\n The minimum value is ", minval());
}
int minval(int min)

Adak told you already about the missing format specifier.

Another problem is that you defined your function "minval" to take one argument, but in main() you call it without one.

But as I understand it your function should take three arguments and return the smallest of them.
Here are two examples for using such a function:

Code:

int min = minval(3, 1, 2) // "min" should be 1

int a = 100, b = 23, c = 5;
int min2 = minval(a, b, c) // "min2" should be 5

Bye, Andreas